JEE Main 31-Jan-2024 Shift 1 Solved Paper

Section: Physics
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Question : 58 of 90
 
Marks: +1, -0
The depth below the surface of sea to which a rubber ball be taken so as to decrease its volume by 0.02% is ______m.
(Take density of sea water =103kgm3, Bulk modulus of rubber =9×108Nm2, and g=10ms2 )
[31-Jan-2024 Shift 1]
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