{\A}_{( {\g})} ⇌ {\B}_{( {\g})}+\frac{ {\C}}{2}( {\g}) The correct relationship between K_P, \alpha and equilibrium pressure P is [31-Jan-2024 Shift 2]

Correct Answer is : KP=α3∕2P1∕2(2+α)1∕2(1−α)

K_P= {\alpha^{1 \/ 2} P^{1 \/ 2}}/{(2+\alpha)^{1 \/ 2}}

K_P= {\alpha^{3 \/ 2} P^{1 \/ 2}}/{(2+\alpha)^{1 \/ 2}(1-\alpha)}

K_P= {\alpha^{1 \/ 2} P^{3 \/ 2}}/{(2+\alpha)^{3 \/ 2}}

K_P= {\alpha^{1 \/ 2} P^{1 \/ 2}}/{(2+\alpha)^{3 \/ 2}}

JEE Main 31-Jan-2024 Shift 2 Solved Paper

Section: Chemistry

Question : 71 of 90

Marks: +1, -0

A(g)⇌B(g)+‌

(g)‌‌ The correct relationship between KP,α and equilibrium pressure P is

[31-Jan-2024 Shift 2]

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