Let \\alpha^{\to} = 3i^{\^} + j ^{\^} and\overrightarrow{\\beta}=2i ^{\^} - j ^{\^}+3 k^{\^} . If \beta^{\to} = \beta_1^{\to}- \beta_2^{\to} , where \beta_1^{\to} is parallel to \alpha^{\to} and \beta_2^{\to} is perpendicular to \alpha^{\to} , then \beta_1^{\to}\times \beta_2^{\to} is equal to: [9 Apr 2019 Shift 1]

Correct Answer is : 12(−3^i+9^j+5 ^k)

\frac{1}{2}(-3 {i}↖ {\^} +9 \stackrel{\^}{j}+5 \stackrel{\^}{k})

\frac{1}{2}( 3 {i}↖ {\^} -9 \stackrel{\^}{j}+5 \stackrel{\^}{k})

( 3 {i}↖ {\^} -9 \stackrel{\^}{j}-5 \stackrel{\^}{k})

( -3 {i}↖ {\^} +9 \stackrel{\^}{j}+5 \stackrel{\^}{k})

JEE Main 9 Apr 2019 Paper 1 Solved Paper

Section: Mathematics

Question : 69 of 90

Marks: +1, -0

Let

→

and

→

−

. If

→

β1

−

→

β2

, where

→

β1

is parallel to

→

and

→

β2

is perpendicular to

→

, then

→

β1

→

β2

is equal to:

[9 Apr 2019 Shift 1]

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