The solution of the differential equation x \frac{d y}{d x}+2 y=x^{2},(x \\neq0) with {y} (1)=1 , is: [9 Apr 2019 Shift 1]

Correct Answer is : y= x24+ 34x2

y= \frac{4}{5} x^{3}+ {1}/{5 x^{2}}

y= \frac{3}{4} x^{2}+ {1}/{4 x^{2}}

JEE Main 9 Apr 2019 Paper 1 Solved Paper

Section: Mathematics

Question : 77 of 90

Marks: +1, -0

The solution of the differential equation x

+2y=x2,(x≠0) with y (1)=1 , is:

[9 Apr 2019 Shift 1]

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