JEE Main 9 Apr 2019 Paper 2 Solved Paper

Given the surtactrant solution has molar concentration is 10−3M . Volume ofsolution = 10mL
∴ no. of moles of surtactant =10×10−3×10−3 moles =10−5 moles
No. of polarheads = 6×1023×10−5
=6×1018
Area coverd on polar substrate =0.24×10{4} m2
a2×6×1018=2.4×10−5
a2=4×10−24
a=2×10−12m
∴a=2.0pm