Consider the following cases of standard enthalpy of reaction (∆ {\H}_{ {\r}}^{\circ}. in {\kJ} {\mol}^{-1}) {\C}_2 {\H}_6( {\g})+\frac{7}{2} {\O}_2( {\g}) \rightarrow 2 {\CO}_2( {\g})+3 {\H}_2 {\O}( {\I}) ∆ {\H}_1^{\circ} =-1550 {\C} \text{ (graphite) }+ {\O}_2( {\g}) \rightarrow {\CO}_2( {\g}) ∆ {\H}_2^{\circ}=-393.5 {\H}_2( {\g})+\frac{1}{2} {\O}_2( {\g}) \rightarrow {\H}_2 {\O}( {\I}) ∆ {\H}_3^{\circ}=-286 The magnitude of ∆ {\H}_{ {\C}_2 {\H}_6( {\g})}^{\circ} is ________kJ {\mol}^{-1} (Nearest integer). [22 Jan 2025 Shift 2]

Chemical Thermodynamics Part 2

Section: Chemistry

Question : 20 of 100

Marks: +1, -0

Consider the following cases of standard enthalpy of reaction (∆Hr∘. in kJ‌mol−1)
‌C2H6(g)+‌

O2(g)⟶2CO2(g)+3H2O(I)∆H1∘ ‌=−1550
‌C‌ (graphite) ‌+O2(g)⟶CO2(g)∆H2∘=−393.5
‌H2(g)+‌

O2(g)⟶H2O(I)∆H3∘=−286
The magnitude of ∆HC2H6(g)∘ is ________kJ mol−1 (Nearest integer).

[22 Jan 2025 Shift 2]

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