Let K be the sum of the coefficients of the odd powers of {\x} in the expansion of (1+x)^{99}. Let a be the middle term in the expansion of (2+ {1}/{\sqrt{2}}) ^{200}. If {{ }^{200} {\C}_{99} {\K}}/{ {\a}}= {2^l {\m}}/{ {\n}}, where {\m} and {\n} are odd numbers, then the ordered pair (ℓ, {\n}) is equal to : [29-Jan-2023 Shift 2]

Binomial Theorem Part 2

Section: Mathematics

Question : 48 of 100

Marks: +1, -0

Let K be the sum of the coefficients of the odd powers of x in the expansion of (1+x)99. Let a be the middle term in the expansion of (2+‌

√2

)200. If ‌

‌200C99K

=‌

2lm

, where m and n are odd numbers, then the ordered pair (ℓ,n) is equal to :

[29-Jan-2023 Shift 2]

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