Let A= \{\theta \in(0,2 \pi): \frac{1+2 i \sin \theta}{1-i \sin \theta}. is purely imaginary \}. Then the sum of the elements in A is. [8-Apr-2023 shift 2]

Complex Numbers Part 2

Section: Mathematics

Question : 63 of 97

Marks: +1, -0

Let A={θ∈(0,2π):‌

1+2isin‌θ

1−isin‌θ

. is purely imaginary }. Then the sum of the elements in A is.

[8-Apr-2023 shift 2]

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