For {n} \in N, let {S}_{ {n}}=\{z \in C:| z-3+2 i|=\frac{ {n}}{4}\} and {T}_{ {n}}=\{z \in C:| z-2+3 i|=\frac{1}{ {n}}\}. Then the number of elements in the set \{n \in N: S_{n} \cap T_{n}=\phi\} is : [25-Jul-2022-Shift-1]

Complex Numbers Part 2

Section: Mathematics

Question : 89 of 97

Marks: +1, -0

For n∈N, let Sn={z∈C:|z−3+2i|=‌

} and Tn={z∈C:|z−2+3i|=‌

}.
Then the number of elements in the set {n∈N:Sn∩Tn=φ} is :

[25-Jul-2022-Shift-1]

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