Let {\A}=\{2,3,4\} and {\B}=\{8,9,12\}. Then the number of elements in the relation {\R}= \{ ( ( {\a}_1, {\b}_1) , ( {\a}_2, {\b}_2) ) \in( {\A} \times. {\B}, {\A} \times {\B}): {\a}_1 divides {\b}_2 and {\a}_2 divides {\b}_1\} is [10-Apr-2023 shift 2]

Sets and Relations Part 1

Section: Mathematics

Question : 54 of 112

Marks: +1, -0

Let A={2,3,4} and B={8,9,12}. Then the number of elements in the relation R={((a1,b1),(a2,b2))∈(A×. B,A×B):a1 divides b2 and a2 divides b1} is

[10-Apr-2023 shift 2]

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