Let f: R \to R be defined as f(x)=e^{-x} \sin x. If F:[0,1] \to R is a differentiable function, such that F(x)=\int_{0}^{x} f(t) d t, then the value of \int_{0}^{1}[F^{'}(x)+f(x)] e^{x} d x lies in the interval [17 Mar 2021 Shift 2]

Correct Answer is : [330360,331360]

[\frac{327}{360}, \frac{329}{360}]

[\frac{330}{360}, \frac{331}{360}]

\frac{331}{360}, \frac{334}{360}

[\frac{335}{360}, \frac{336}{360}]

Definite Integrals Part 2

Section: Mathematics

Question : 87 of 100

Marks: +1, -0

Let f:R→R be defined as f(x)=e−x‌sin‌x. If F:[0,1]→R is a differentiable function, such that F(x)=

∫

f(t)dt, then the value of

∫

[F′(x)+f(x)]exdx lies in the interval

[17 Mar 2021 Shift 2]

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