Let f, g:(0, \infty) \rightarrow R be two functions defined by f(x)=\int_{-x}^{x} (|t|-t^2) e^{-t^2} \dt and g(x)=\int_{0}↖{}{x^2} t^{1 \/ 2} e^{-t} \dt. Then the value of (f (\sqrt{\log _e 9}) +g (\sqrt{\log _e 9}) ) is equal to [31-Jan-2024 Shift 2]

Definite Integrals Part 3

Section: Mathematics

Question : 63 of 115

Marks: +1, -0

Let f,g:(0,∞)⟶R be two functions defined by f(x)=

∫

−x

(|t|−t2)e−t2‌dt and g(x)=

‌

∫

x2t1∕2e−t‌dt. Then the value of (f(√loge9)+g(√loge9)) is equal to

[31-Jan-2024 Shift 2]

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