Definite Integrals Part 3
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Question : 86 of 115
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Let for x ∈ R , S 0 ( x ) = x , S k ( x ) = C k x + k
S k − 1 ( t ) dt where C 0 = 1 , C k = 1 −
S k − 1 ( x ) dx , k = 1 , 2 , 3 , . . . Then S 2 ( 3 ) + 6 C 3 is equal to _______.
[13-Apr-2023 shift 1]
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