© examsiri.com
Question : 68 of 100
Marks:
+1,
-0
Solution:
+ 3
sec2 x , y =
sec2 x
I.F. =
e3∫sec2xdx =
e3tanx or , y
e3tanx =
∫sec2x .
e3tanx dx
or y
e3tanx =
e3tanx + C ... (1)
Given
y
()=4/3$$
∴
.
e3 =
e3 + C
∴ C =
e3 Now put x =
− in eq (1)
∴ y .
e−3 =
e−3+e3 ∴ y =
+e6 ∴ y
(−) =
+e6
© examsiri.com
Go to Question: