The solution of the differential equation (1+y^2) + (x-e^{\tan ^{-1} y}) \frac{d y}{d x}=0, \text{ is } [AIEEE 2003]

Correct Answer is : 2xetan−1y=e2tan−1y+k

x e^{2 \tan ^{-1} y}=e^{\tan ^{-1} y}+k

2 x e^{\tan ^{-1} y}=e^{2 \tan ^{-1} y}+k

x e^{\tan ^{-1} y}=\tan ^{-1} y+k

Differential Equations Part 1

Section: Mathematics

Question : 98 of 100

Marks: +1, -0

The solution of the differential equation
(1+y2)+(x−etan−1y)‌

=0,‌ is ‌

[AIEEE 2003]

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