If \cos ^{-1} x-\cos ^{-1} \frac{y}{2}=\\alpha, where -1 \leq x \\leq1,-2 \\leq y \\leq 2, x \\leq\frac{y}{2} then for all x,y 4 x^{2}-4 x y \cos \\alpha+y^{2} is equal to : [10 Apr 2019 Shift 2]

4 \cos ^{2} \\alpha+2 x^{2} y^{2}

4 \sin^{2} \\alpha- 2 x^{2} y^{2}

Inverse Trigonometric Functions

Section: Mathematics

Question : 79 of 95

Marks: +1, -0

If cos−1x−cos−1

=α, where −1≤x≤1,−2≤y≤2,x≤

then for all x,y 4x2−4xy‌cos‌α+y2 is equal to :

[10 Apr 2019 Shift 2]

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