Limits, Continuity and Differentiability Part 2

Section: Mathematics

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Question : 46 of 100

Marks: +1, -0

lim

x→‌

π

2

(tan2x((2sin2x+3‌sin‌x+4)‌

1

2

−(sin2x+6‌sin‌x+2)‌

1

2

)) is equal to

[25-Jun-2022-Shift-2]

‌
1
12
−‌
1
18
−‌
1
12
‌
1
6

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