The vectors \overrightarrow{a} and \overrightarrow{b} are not perpendicular and \overrightarrow{c} and \overrightarrow{d} are two vectors satisfying \overrightarrow{b} \times \overrightarrow{c}=\overrightarrow{b} \times \overrightarrow{d} and \overrightarrow{a} \cdot \overrightarrow{d}=0. Then the vector \overrightarrow{d} is equal to [AIEEE 2011]

Correct Answer is : →c−(→a⋅c→a⋅b)→b

\overrightarrow{c}+ ( \overrightarrow{{a . c}}/\overrightarrow{{a . b}}) \overrightarrow{b}

\overrightarrow{b}+ ( \overrightarrow{{b} \cdot \overrightarrow{c}}/\overrightarrow{{a} \cdot \overrightarrow{b}}) \overrightarrow{c}

\overrightarrow{c}- ( \overrightarrow{{a} \cdot c}/\overrightarrow{{a} \cdot b}) \overrightarrow{b}

\overrightarrow{b}- ( \overrightarrow{{b . c}}/\overrightarrow{{a} \overrightarrow{b}}) \overrightarrow{c}

Vector Algebra Part 1

Section: Mathematics

Question : 66 of 100

Marks: +1, -0

The vectors

→

and

→

are not perpendicular and

→

and

→

are two vectors satisfying

→

and

→

⋅

→

=0. Then the vector

→

is equal to

[AIEEE 2011]

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