© examsiri.com
Question : 68 of 100
Marks:
+1,
-0
Solution:
=×⇒⋅=⋅(×)⇒⋅=0⇒(b1+b2+b3)⋅(−−)=0where
=b1+b2+b3b1−b2−b3=0‌‌...(i) ‌‌ and ‌⋅=3‌⇒(−)⋅(b1+b2+b3)=3‌⇒b2−b3=3From equation
(i)‌b1=b2+b3=(3+b3)+b3=3+2b3‌=(3+2b3)+(3+b3)+b3 From the option given, it is clear that
b3 equal to either 2 or
−2.
b3=2then
=7+5+2 which is not possible
If
b3=−2, then
=−+−2
© examsiri.com
Go to Question: