Semiconductor Electronics Part 2

According to given circuit diagram, Let I current is flowing through the circuit.
∴ Kirchhoff’s voltage loop equation will be
10‌sin‌ω‌t−IR−3=0
IR=V=10‌sin‌ω‌t−3
∴ At time, t=0,V=0−3=−3V ...(i)
t=

T

4

,V=10‌sin(

2π

T

).

T

4

−3
=10−3=7V ...(ii)
t=

T

2

to T, diode is in reverse bias.
∴ V = 0 ...(iii)
We see that at t=0,V=−3 and

T

2

≤t≤T,V=0
Therefore, no waveforms exist in option (a), (b) (c) and (d), which satisfies above condition.
Hence, no option is correct.