JEE Mains 03-Sep-2020 Shift 2 Solved Paper

Section: Mathematics

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Question : 52 of 75

Marks: +1, -0

If the value of the integral

1∕2

∫

0

x2

(1−x2)3∕2

dx is

k

6

, then k is equal to

[3 Sep 2020 Shift 2]

2√3−π
3√2+π
3√2−π
2√3+π

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