Let e_{1} and e_{2} be the eccentricities of the ellipse,{x^{2}}/{25}+ {y^{2}}/{b^{2}}=1(b<5) and the hyperbola {x^{2}}/{16}- {y^{2}}/{b^{2}}=1 respectively satisfying e_{1} e_{2}=1 . If \\alpha and \\beta are the distances between the foci of the ellipse and the foci of the hyperbola respectively, then the ordered pair (\\alpha, \\beta) is equal to : [3 Sep 2020 Shift 2]

JEE Mains 03-Sep-2020 Shift 2 Solved Paper

Section: Mathematics

Question : 67 of 75

Marks: +1, -0

Let e1 and e2 be the eccentricities of the ellipse,

=1(b<5) and the hyperbola

−

=1 respectively satisfying e1e2=1 . If α and β are the distances between the foci of the ellipse and the foci of the hyperbola respectively, then the ordered pair (α,β) is equal to :

[3 Sep 2020 Shift 2]

(8,10)
(8,12)
(
20
3
,12)
(
24
5
,10)

Validate

Go to Question:

Prev Question

Next Question