JEE Mains 05-Sep-2020 Shift 1 Solved Paper

Section: Mathematics

Question : 59 of 75

Marks: +1, -0

If ∫(e2x+2ex−e−x−1)e(ex+e−x)dx =g(x)e(ex+e−x)+c, where c is a constant of integration, then g(0) is equal to :

[5 Sep 2020 Shift 1]

Go to Question:

Prev Question

Next Question