JEE Mains 12-Apr-2023 Shift 1 Solved Paper

Section: Physics
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Question : 53 of 90
 
Marks: +1, -0
A common example of alpha decay is
‌‌92238U→‌90234‌Th+‌2He4+Q
‌‌ Given : ‌
‌‌92238U=238.05060u,
‌‌234‌Th=234.04360u,
‌90
‌‌24‌He=4.00260u‌ and ‌
‌lu=931.5‌
MeV
c2

The energy released (Q) during the alpha decay of ‌238U is _______ MeV
[12-Apr-2023 shift 1]
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