If I = \int{dx}/{x^4 \sqrt{a^2+x^2} then I equals

Correct Answer is : 1a4[1x√a2+x2−132x2(a2+x2)32]+c

1/a^4[1/x \sqrt{a^2+x^2}-1/{32x^2} \sqrt{a^2+x^2}] + c

1/a^4[1/x \sqrt{a^2+x^2}-1/{32x^2} ({a^2+x^2})^{3/2}] + c

1/a^4[1/x \sqrt{a^2+x^2}-1/{2\sqrtx} ({a^2+x^2})^{3/2}] + c

1/a^4[1/x \sqrt{a^2+x^2}+1/{3x^3}\sqrt{a^2+x^2}] + c

JEE Mains 2020 Model Paper 4 New Pattern

Question : 65 of 75

Marks: +1, -0

If I = ∫

x4√a2+x2

then I equals

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