JEE Mains 24-Jan-2023 Shift 2 Solved Paper

Section: Mathematics

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Question : 65 of 90

Marks: +1, -0

If f(x)=x3−x2f′(1)+xf′′(2)−f′′′(3),x∈R, then

[24-Jan-2023 Shift 2]

3f(1)+f(2)=f(3)
f(3)−f(2)=f(1)
2f(0)−f(1)+f(3)=f(2)
f(1)+f(2)+f(3)=f(0)

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