Home Back

JEE Mains 25-July-2022 Shift 1 Solved Paper

Section: Chemistry
© examsiri.com
Question : 89 of 90
 
Marks: +1, -0
The number of sp3 hybridised carbons in an acyclic neutral compound with molecular formula C4H5N is
[25-Jul-2022-Shift-1]
  • Your Answer:
Validate
Go to Question:
Prev Question
Next Question