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Question : 71 of 120
Marks:
+1,
-0
Solution:
Given,
α=3i−k,|β|=√5 and
α⋅β=3 Now,
|α|=√9+1=√10 α⋅β=3 ⇒|α||β|cosθ=3 ⇒√10√5cosθ=3 ⇒cosθ= =√ since,
α and
β are adjacent sides of the parallelogram.
∴ Area of parallelogram
=|α×β| =|α||β|sinθ =√10√5× (∵|n|=1) =√41
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