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Question : 89 of 120
Marks:
+1,
-0
Solution:
Given that,
a=++ b=4+3+4 and
c=+α+β since,
a,b and
c are coplanar
Then,
||=0 ⇒1(3β−4α)−1(4β−4)+1(4α−3)=0
⇒3β−4α−4β+4+4α−3=0 ⇒β=1 Also,
|c|=√3 ⇒√1+α2+β2=√3 ⇒α2=1⇒α=±1
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