KVPY SA Exam 2015 Question Paper

Question : 43 of 80

Marks: +1, -0

The maximum number of isomeric ethers with the molecular formula

C_4H _10O

Solution:

C_4H _10O

{CH_3–CH_2–CH_2–O–CH_3}↙{\Methoxy \propane }\;\;\;{CH_3– {CH↖{∣ }}↖{CH_3}–O–CH_3}↙{2 \metnoxy \propane }\;\;\;{CH_3–CH_2–O–CH_2–CH_3}↙{\Ethoxy \Ethane}

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