KVPY SA Exam 2015 Question Paper

Question : 67 of 80

Marks: +1, -0

1 Kg of ice at -20 °C is mixed with 2 Kg o f water at 90 °C.
Assuming that there is no loss of energy to the environment, what will be the final temperature of the mixture? (Assume latent heat of ice = 334.4 KJ/Kg, specific heat of water and ice are 4.18 kJ/(kg.K) and 2.09 kJ/(kg.K), respectively.)

30 °C
0°C
80 °C
45 °C

Validate

Solution:

Total heat gain = 20 × 2.09 + 334.4 KJ = 376.2 kJ
Total heat loss = 752.4 kJ
Heat gain required = 752.4 – 376.2 = 376.2 kJ
376.2 = ms

∆

T
376.2 = 3 × 4.18 ×

∆

∆

T = 30 centigrate
T

_\final

= 30ºC

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