Madhya Pradesh Police Exam Model Paper 10

Question : 74 of 100

Marks: +1, -0

In a ΔPQR, PQ = QR, ∠Q = x and ∠P = 3x – 15°. Then ∠Q is.

Solution:

Given:
PQ = QR, ∠Q = x and

∠P = 3x – 15°

Concept used:
The Sum of all angles of a triangle is 180°.
Calculation:

PQ = QR

⇒ ∠PRQ = ∠RPQ = 3x – 15°

⇒ ∠P + ∠Q + ∠R = 180°

⇒ (3x – 15°) + x + (3x – 15°) = 180°

⇒ 2(3x – 15°) + x = 180°

⇒ 6x – 30° + x = 180°

⇒ 7x = 210°

⇒ x = 30°

∴ ∠Q is 30°.

Go to Question:

Prev Question

Next Question