Madhya Pradesh Police Exam Model Paper 10

Given:
∠ROS = 90°
∠POS = 35°
Calculation:
Sum of angles on a straight line is 180°
$\Rightarrow \angle \mathit{R}\mathit{O}\mathit{S}+\angle \mathit{R}\mathit{O}\mathit{Q}=180°$
$\Rightarrow \angle \mathit{R}\mathit{O}\mathit{Q}=180°-90$ °
$\Rightarrow \angle \mathit{R}\mathit{O}\mathit{Q}=90°$
$\Rightarrow \angle \mathit{P}\mathit{O}\mathit{S}+\angle \mathit{P}\mathit{O}\mathit{Q}=180°$
$\Rightarrow \angle \mathit{P}\mathit{O}\mathit{Q}=180°-35°$
$\Rightarrow \angle \mathit{P}\mathit{O}\mathit{Q}=145°$
$\Rightarrow \angle \mathit{P}\mathit{O}\mathit{Q}-\angle \mathit{R}\mathit{O}\mathit{Q}=145°-90°$
$\therefore \angle \mathit{P}\mathit{O}\mathit{Q}-\angle \mathit{R}\mathit{O}\mathit{Q}=55°$
The correct option is 1 i.e. 55°
Sum of angles on a straight line is 180°