Madhya Pradesh Police Exam Model Paper 8

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Question : 62 of 100

Marks: +1, -0

The simplified form of

X^2 × (X^{13} ÷ X^{15})

is:

0
X
$X^2$
1

Solution:

Formula

a^x × a^y = a^{(x + y)}

a^x ÷ a^y = a^{(x - y)}

Calculation

X^2 x (X^{13} ÷ X^{15})

⇒ X^2 ×X^{(13 - 15)}

⇒ X^2 x X^{-2}

⇒ X^{2 - 2}

⇒ X^0

⇒ 1

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