Management Aptitude Test 2016 Paper

(a) Let cost price of article be ₹ x.
And profit = 17.5%$$[given]
∴ SP = $\left(\frac{100+\mathrm{Profit}\%}{100}\right)\times \mathrm{CP}=\mathit{₹}\frac{117.5}{100}\mathit{x}$
Again, let new CP be ₹ X'.
Then,$$ X '= $\mathit{₹}\frac{92}{100}\mathit{x}$
and new profit = 30%
According to the question,
$\frac{130}{100}\times \frac{92}{100}\mathit{x}-\frac{117.5}{100}\mathit{x}=11.55$
$\Rightarrow 130\times 92\mathit{x}-117.5\mathit{x}$ × 100 = 11.55 × 10000
$\Rightarrow 11960\mathit{x}-11750\mathit{x}=115500$
$\Rightarrow 210\mathit{x}=115500$
$\Rightarrow \mathrm{x}=\mathit{₹}550$