Management Aptitude Test 2017 Paper

(dl 45
Here, n(H) = 47 -15 = 32,
n(C) = 53 - 15 = 38
and n(F) = 72 - 15 = 57
We know that,
n (H ∪ C ∪ F) = n (H ) + n(C) + n( f) - n(H ∩ C) - n(C ∩ F ) - n(H ∩ F ) + n(H ∩ C ∩ F)
⇒ 97 = 32 + 38 + 57 - n(H ∩ C) - n(C ∩ F ) - n(H ∩ F ) + 15
⇒ n(H ∩ C) + n(C ∩ F ) + n(H ∩ F ) = 142 - 97 = 45
Number of students who play exactly two games are 45.