Management Aptitude Test 2017 Paper

(a) $\frac{16}{69}$
Let E = Event of choosing defective shirt.
A = Event of choosing defective shirt from process A
Similarly B and C be the event choosing shirt from process B and C.
Now, P(A) = $\frac{25}{100}$ , P(B) = $\frac{35}{100}$, P(C) = $\frac{40}{100}$
P(E/A) = $\frac{5}{100}$ , P(E/B) = $\frac{4}{100}$ , P(E/C) = $\frac{2}{100}$
Now, by Baye's theorem,

=
= $\frac{80}{125+140+80}$ = $\frac{80}{345}=\frac{16}{69}$
Probability of defective shirt selected from process C is $\frac{16}{69}$.