Management Aptitude Test Dec 2013 Paper

(b) Let the winning post be at a distance of x m.
∴ If both reaches at sam e time, then distance covered by B = x - 80 m.
Given that, S peed of A = 1 $\frac{2}{3}$ Speed of B
$\frac{\mathit{S}\mathit{p}\mathit{e}\mathit{e}\mathit{d}\mathit{o}\mathit{f}\mathit{A}}{\mathit{S}\mathit{p}\mathit{e}\mathit{e}\mathit{d}\mathit{o}\mathit{f}\mathit{B}}=\frac{5}{3}$
We know that,
Speed of A : Speed of B =Distance covered by A : Distance covered by B
$\frac{\mathit{x}}{\mathit{x}-80}=\frac{5}{3}$
⇒ 3x = 5x - 400
⇒ x = 200 m