Management Aptitude Test Dec 2019 Paper

Question : 105 of 200

Marks: +1, -0

Two die are thrown simultaneously. What is the probability of getting a number other than 4 on any dice?

Solution:

Here,

n(S)=6 × 6=36

and

\E=

Event of getting a number other than 4 on any dice

=\{(1,1),(1,2),(1,3),(1,5),(1,6),(2,1),(2,2),(2,3),(2,5),(2,6), (3,1),(3,2),(3,3),(3,5),(3,6),(5,1),(5,2),(5,3),(5,5),(5,6), (6,1),(6,2),(6,3),(6,5),(6,6)\}

∴\P(\E)={n(E)}/{n(S)}={25}/{36}

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