Management Aptitude Test Sep 2011 Paper

(2) For first year, P = ₹ 6000
SI = $\frac{6000\times 10\times 1}{100}$ = ₹ 600
At the end of first year, amount = ₹ (6000 + 600)= ₹ 6600
Return back = ₹ 2000
For second year, P = ₹ (6600 - 2000) = ₹ 4600
SI = $\frac{4600\times 10\times 1}{100}$ = ₹ 460
At the end of second year, amount = ₹ (4600 + 460) = ₹ 5060
Return back = ₹ 2000
For third year, P = ₹ (5060 - 2000) = ₹ 3060
SI = $\frac{3060\times 10\times 1}{100}$ = ₹ 306
∴ Amount returned in third year
= ₹ (3060 + 306 )= ₹ 3366