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Question : 56 of 70
Marks:
+1,
-0
Solution:
The lines are parallel to the vectors
b1=+2−and
b2=−+−2 ∴ The plane normal to the vector n is
b1×b2=|| =−3+3+3 The required plane passes through
(+) and is normal to the vector
n.
∴ Its equation is
r.n=a.n ⇒
r.(−3+3+3) =(+).(−3+3+3) ⇒
r.(−3+3+3)=−3+3 ⇒
r.(−++)=0
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