© examsiri.com
Question : 26 of 50
Marks:
+1,
-0
Solution:
||=||=||=1 ⋅=(1)(1)‌cos‌θ=cos‌θ and
⋅=cos‌θ,⋅=cos‌θ ]2=|| ⋅ | ⋅ | ⋅ |
| â‹… | â‹… | â‹… |
| â‹… | â‹… | â‹… |
|=|| 1 | cos‌θ | cos‌θ |
| cos‌θ | 1 | cos‌θ |
| cos‌θ | cos‌θ | 1 |
| Operate
R1→R1+R2+R3 =(1+2‌cos‌θ)|| 1 | 1 | 1 |
| cos‌θ | 1 | cos‌θ |
| cos‌θ | cos‌θ | 1 |
| Operate
C2→C2−C1;C3→C3−C1 =(1+2‌cos‌θ)|| 1 | 0 | 0 |
| cos‌θ | 1−cos‌θ | 0 |
| cos‌θ | 0 | 1−cos‌θ |
| =(1+2‌cos‌θ)(1−cos‌θ)2 ∴[]=(1−cos‌θ)√1+2‌cos‌θ
© examsiri.com
Go to Question: