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Question : 76 of 100
Marks:
+1,
-0
Solution:
r=(+)+λ(2−+) . . . (i)
r=(2+−)+µ(3−5+2) . . . (ii)
Compare with vector equation
r=a+λb a1=+=2−+ a2=2+−,b2=3−5+2 d=|| . . . (iii)
b1×b2=|| b1×b2=(−2+5)−(4−3)+(−10+3) =3−−7 |b1×b2|=√(3)2+(−1)2+(−7)2 Also
a2−a1=(2+−)+(+)=−... (iv)
d=|(3−−7)(−|=||=
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