MHTCET 13 May 2023 Shift 2 Solved Paper

The ball executes free fall until it hits the upper surface of glycerine.
∴ Velocity of ball when it reaches the upper surface of glycerine is given as,
v‌=√2gh
‌=√2×9.8×1.5
⇒‌‌v2‌=29.4m∕ s2
Using the formula, v2−u2=2as inside the glycerine.
We have,
0−29.4=−2×(2.66)×h
(∵h= distance travelled inside glycerine)
⇒‌‌h=5.5m
∴ The height of glycerine in jar will be 5.5m.