\int \frac{x-3}{(x-1)^3} e^x \dx=

Correct Answer is : ex(1(x−1)2)+c, where c is constant of integration

e^x (\frac{1}{(x-1)^2}) +c, where c is constant of integration

e^x (\frac{1}{x+1}) +c, where c is constant of integration

e^x ((x-1)^2) +c, where c is constant of integration

e^x ((x-1)^3) +c, where c is constant of integration

MHTCET 13 May 2023 Shift 2 Solved Paper

Section: Mathematics

Question : 70 of 150

Marks: +1, -0

∫‌

x−3

(x−1)3

ex‌dx=

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