MHTCET 13 May 2023 Shift 2 Solved Paper

Section: Mathematics

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Question : 77 of 150

Marks: +1, -0

The solution of (1+xy)y‌dx+(1−xy)xdy=0 is

log(‌
x
y
)+‌
1
xy
=k, where k is constant of integration
log(‌
x
y
)=‌
1
xy
+k, where k is constant of integration
log(‌
x
y
)+xy=k, where k is constant of integration
log(‌
x
y
)=xy+k, where k is constant of integration

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