The de-Broglie wavelength (\lambda) of a particle is related to its kinetic energy (E) as

Correct Answer is : λ∝E−12

\lambda \propto {\E}^{\frac{1}{2}}

\lambda \propto {\E}^{-\frac{1}{2}}

MHTCET 14 May 2023 Shift 1 Solved Paper

Section: Physics

Question : 117 of 150

Marks: +1, -0

The de-Broglie wavelength (λ) of a particle is related to its kinetic energy (E) as

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