\int \binom{ \sin 2 x (1-\frac{3}{2} \cos x) }/{e^{ \sin ^2 x+\cos ^3 x}} \dx=

Correct Answer is : −e−(sin2x+cos3x)+c, where c is a constant of integration.

{\e}^{ \sin ^2 x+\cos ^3 x}+{c}, where {c} is a constant of integration.

- {\e}^{- ( \sin ^2 x+\cos ^3 x) }+ {\c}, where {\c} is a constant of integration.

{\e}^{- ( \sin ^2 x+\cos ^3 x) ^2}+{c}, where {\c} is a constant of integration.

{\e}^{ \sin ^2 x+\cos x}+ {\c}, where {\c} is a constant of integration.

MHTCET 14 May 2023 Shift 1 Solved Paper

Section: Mathematics

Question : 70 of 150

Marks: +1, -0

∫‌

sin‌2x(1−

‌cos‌x)

esin‌2x+cos3x

‌dx=

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