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Question : 52 of 150
Marks:
+1,
-0
Solution:
‌|c−|=2√2‌⇒||2+||2−2(a⋅c)=8‌⇒||2+9−2||=8‌‌...[∵a⋅c=||‌ (given) ‌]‌⇒(||−1)2=0‌⇒||=1Now,
|(a×b)×c|=‌|a×b|||sin‌‌=‌|a×b|(1)(‌)=‌‌‌...[∵a×b=2−2+]
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