The value of \int {\e}^x (\frac{x^2+4 x+4}{(x+4)^2}) {\d} x is:

Correct Answer is : ex(xx+4)+c, where c is a constant of integration.

{\e}^x (\frac{x}{x+4}) + {\c}, where {\c} is a constant of integration.

{\e}^x (\frac{4}{x+4}) + {\c}, where {\c} is a constant of integration.

{\e}^x (\frac{x}{(x+4)^2}) + {\c}, where {\c} is a constant of integration.

{\e}^x (\frac{4}{(x+4)^2}) + {\c}, where {\c} is a constant of integration.

MHTCET 14 May 2023 Shift 2 Solved Paper

Section: Mathematics

Question : 69 of 150

Marks: +1, -0

The value of ∫ex(‌

x2+4x+4

(x+4)2

)dx is:

Go to Question:

Prev Question

Next Question